2n^2=298

Solution for 2n^2=298 equation:

2n^2=298

We move all terms to the left:

2n^2-(298)=0

a = 2; b = 0; c = -298;
Δ = b2-4ac
Δ = 02-4·2·(-298)
Δ = 2384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2384}=\sqrt{16*149}=\sqrt{16}*\sqrt{149}=4\sqrt{149}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{149}}{2*2}=\frac{0-4\sqrt{149}}{4}
=-\frac{4\sqrt{149}}{4}
=-\sqrt{149}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{149}}{2*2}=\frac{0+4\sqrt{149}}{4}
=\frac{4\sqrt{149}}{4}
=\sqrt{149}
$